2x^2+34x-18=0

Solution for 2x^2+34x-18=0 equation:

2x^2+34x-18=0

a = 2; b = 34; c = -18;
Δ = b2-4ac
Δ = 342-4·2·(-18)
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-10\sqrt{13}}{2*2}=\frac{-34-10\sqrt{13}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+10\sqrt{13}}{2*2}=\frac{-34+10\sqrt{13}}{4}
$